A ball is sent up vertically from h tower of height 58.8m with a velocity of 4.9m/s. what is tha time taken by it to reach the ground
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Given, Maximum height = 58.8 m
The velocity with which it was thrown = Initial velocity = 4.9 m/s
Time taken to reach back to the ground = Time of flight = 2u / g
= 2 (4.9) / 9.8
= 9.8 / 9.8
= 1 sec
∴ Time taken to reach the ground = 1 sec
Hope my answer helps you..
The velocity with which it was thrown = Initial velocity = 4.9 m/s
Time taken to reach back to the ground = Time of flight = 2u / g
= 2 (4.9) / 9.8
= 9.8 / 9.8
= 1 sec
∴ Time taken to reach the ground = 1 sec
Hope my answer helps you..
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