Question

A ball is shot at a ground level at an angle of 60° with the horizontal with an initial velocity of 100 m/s

Answer 1

Correct Question :

A ball is shot at a ground level at an angle of 60° with the horizontal with an initial velocity of 100 m/s. How far from the throwing point will the ball attain its original level.

Answer :

Initial velocity = 100 m/s

Angle of projection = 60°

We have to find range of projectile $.$

★ A body is said to be projectile if it is projected into space with some initial velocity and then it continues to move in a vertical plane such that its horizontal acceleration is zero and vertical downward acceleration is equal to g.

• In projectile motion, the horizontal motion and the vertical motion are independent of each other i.e., neither motion affects the other.

For a projectile fired with velocity u at an angle θ with the horizontal,

• Range = u²sin2θ/g

Remember that the horizontal range is same for the angle of projection of θ and (90° - θ).

Therefore we can substitute θ = 30° in the formula of range.

➝ R = u²sin2(30°)/g

➝ R = (100)²sin60°/10

➝ R = 1000 × √3/2

➝ R = 500√3

➝ R = 865 m