Question

A ball is shot from ground level with an initial velocity of 25 m/s directed at an angle of 53° to the horizontal. How much time elapses before the ball strikes the ground?

Answer 1

Answer:

Now, for the same initial velocity

$t = \frac{2 \times 25 \times sin {53}^{0} }{9.8} \\ t = \frac{50}{9.8} \times 0.80 =4 \: sec$