Question

A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36kph to zero in 5s. The angle by which the ball deviates from the vertical. g=10ms-2. Solve. Answer is tan-1(1/5).

Answer 1

★★Question:-

✓✓Ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36kph to zero in 5s. The angle by which the ball deviates from the vertical. (g=10m/s-²)

★★Answer:-

we have,

• $36kmph=10m/s$

we know that,

$v= u+ at$

$a =-\dfrac{10}{5}$

$\boxed{\boxed{{a=-2m/{s}^{s}}}}$

Then,

$g=10m/{s}^{2}$

Net acceleration

$aT={ \sqrt{a^2+g^2}}$

Angle of net acceleration,

$tanθ =\dfrac{a}{g}$

$=\dfrac{2}{10}$

$θ={tan}^{-1}\dfrac{1}{5}$

final answer is,

$\boxed{\boxed{{θ={tan}^{-1}\dfrac{1}{5}}}}$ with vertical✔️✔️

Answer 2

Answer:

Explanation:

We have,

36 kmph = 10 m/s

v=u+at

∴a=−  

5

10

​  

 

∴a=−2m/s  

2

 

Also,

g=10m/s  

2

 

Net acceleration,

a  

T

​  

=  

a  

2

+g  

2

 

​  

 

an angle of net acceleration,

tanθ=  

g

a

​  

=  

10

2

​  

 

∴θ=tan  

−1

(  

5

1

​  

)   with vertical