A ball is thrawn straight upward with a speed v form a point h meter above the ground.The time taken for the ball to strike the ground is
a) v/g[1+√1t2hg/v2]
b) v/g[1-√1-2hg/v2]
c) v/g [1-√1+2hg/v2]
d) v/g [2+2hg/v2]
Answers
Answered by
3
Answer:
Explanation:
s=vt−
2
1
gt
2
Now, at C (maximum height point),
h
‘
=
2g
v
2
So, for journey from C to B,
time =
g
2(h+h
‘
)
=
g
2(h+
2g
v
2
)
=t
2
⇒ total time =t
1
+t
2
=
g
v
(1+
1+
v
2
2hg
)
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