Question

a ball is through in vertically upwards with a initial velocity such that I can reach a maximum height of 15meter if at a same time a stone is dropped from a height of 15meter find ratio of distances travel by them when a cross each other​

Answer 1

projection velocity u of the ball that is thrown to reach 15 m height is calculated using the formula, "

u = (2*9.8*15)^0.5=17.5m/s

Let t be the time when the ball and stone meet at a distance S from ground.

 

S = 17.15×t - (1/2)×9.8×t2.....................(1)

15-S = (1/2)×9.8×t2 ............................(2)

 

solving (1) and (2), we get t = 0.875 s

 

Substitute t=0.875 in (1) and (2), and get the ratio  S/(15-S) = 3

Answer 2

Explanation:

see the attachment.......