Question

A ball is throw up with a velocity of 20m/s. the time for which it will be in space is

Answer 1

Answer:

Explanation:

These questions can be answered by making use of Newton's equations of motion. There are 3 equations of motions.

v=u+at

s=ut+12at2

v2=u2+2as

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

s = distance

In your question, the initial velocity is given as 20m/s, i.e., u=20m/s, the final velocity that the ball can achieve at the maximum height is 0m/s, hence, v=0m/s. Since the only first that cause the acceleration is gravity, a is taken as g where g is acceleration due to gravity, and had a value of 9.81m/s2. But for simplicity, we can take the value of a to be 10m/s2, so a=10m/s2. Now, we need to find, what's s and t.

Note: Since the ball is thro......

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