a ball is throw upwards with a speed of 100 m/s square show that the ball hits the ground with the same speed after returning from the heighest point negalating the air resistance
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The ball is thrown with a speed of 100m/s so if we apply newton laws of motion then we will get the value of maximum height as
u^2 = 2gh.
100*100 = 2×10×h.
Thus
h = 500m.
Now, we got the maximum height of the flight as 500m. Again by applying the newton laws of motion we will get.
As, h = ut + 1/2gt^2.
500 = 100t - 5t^2.
t^2 - 20t + 100 =0.
(t-10)^2 = 0.
So, t=10sec.
Thus, the total time of the flight will be
2×10=20sec.
hope it will help you.....
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