a ball is thrown at a angle theta with horizontal. Its kinetic energy is 100J and it becomes 30 j at highest point. the angle of projection is
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Explanation:
Initial energy = 1/2 mu² = 100J …..........(1)
Where u = initial velocity with which it is thrown.
where m = mass of the ball.
At the top most point there is only horizontal component of velocity:
(ucosθ)
The vertical component will be zero.
So energy at the top most point will be :
= 1/2 mu²cos2θ = 30
=> 100cos2θ = 30 (using equation (1))
=> cosθ = √(30/100) = √(3/10)
=> θ=cos-1√(3/10)
√3/10 = 0.54772.
Cos ⁻¹ 0.54772 = 56.79°
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