Question

A ball is thrown at a speed 10 m per secand what is the hight the ball reached

Answer 1

Answer:

what is the time to find the height at tat point?

Answer 2

Answer:

Velocity at equal height remains equal in magnitude and hence

v

2

=u

2

+2as

20

2

=10

2

+2×10×h

∴h=

2×10

400−100

=

20

300

=15m