Question

A ball is thrown at a speed 40m/s at an angle of 60° with horizontal. Find the maximum hight reached and range of the ball. Take g =10 m/s square

Answer 1

SPEED = 40 m/s

angle = 60 degrees

max height reached = u^2 sin^2 Ф/2g

                                 = 40² * (√3/2)²/2*10

                                 = 60 meters

range = u²sin2Ф/g = 1600*√3/2/10 = 80√3 m