Question

A ball is thrown at a speed of 40m/s at a angle of 60° with horizontal. find it's vertical velocity component
$plz \: answer \: fastly$
​

Answer 1

Given

u=40m/s, θ=600 and g=10m/s2

Maximum Height H Max

$= \frac{2sin2θ}{2gu} =60m$

Range R=

$\frac{sin2θ}{g</p><p>u </p><p>2} </p><p> </p><p> =80 </p><p>2</p><p> </p><p>3m$