Question

a ball is thrown at a speed of 40ms-1 at an angle of 60 degrees with horizontal. Find its vertical velocity component

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I WANT ANSWER WITH EXPLAINATION​

Answer 1

Explanation:

Given u=40m/s, θ=60

0

and g=10m/s

2

Maximum Height H

Max

=

2g

u

2

sin

2

θ

=60m

Range R=

g

u

2

sin2θ

=80

2

3

m

Answer 2

Answer:

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