Question

A ball is thrown at an angle of 30 with horizontal with 30 m/s. The time taken to reach the ground is - ​

Answer 1

$\huge{\underline{\underline{\rm{Answer:-}}}}$

${\underline{\underline{\bf{Given:-}}}}$

• Angle of projection= 30°

• Initial velocity=30 m/s

• Acceleration due to Gravity:- 10 m/s²( let)

${\underline{\underline{\bf{To\:Find:-}}}}$

• Time of projectile

${\underline{\underline{\bf{Solution:-}}}}$

As we know,

Time of projectile:-

$\huge { \sf{\frac{2usin \theta}{g} }}$

putting the values;

$\implies \sf{\frac{2 \times 30 \times sin30}{g} } \\ \\ \implies { \sf{\frac{60 \times \frac{1}{2} }{10} }} \\ \\ \implies \frac{6{ \cancel{0 }}}{2{ \cancel{0}}} \\ \\ \implies {\boxed{ \bf{3 \: s}}}$

${\underline{\underline{\bf{Related\: Knowledge:-}}}}$

Projectile:-

Motion of a body under gravity is known as projectile motion.

Formula of Maximum height:- u²sin²∅/2g

Formula of range:- u²/gsin2∅

Answer 2

★ Question :

A ball is thrown at an angle of 30 with horizontal with 30 m/s. The time taken to reach the ground is ?

★ Answer :

given : velocity = 30 m/s

angle of projectile ,∅= 30°

we know that ;

time taken by the projectile

$= \frac{2u \sin(theta) }{g}$

$= \frac{2 \times 30 \times \sin(30) }{10}$

$= \frac{2 \times 30 \times \frac{1}{2} }{10}$

$= \frac{30}{10}$

$= 3s</strong><strong>e</strong><strong>c</strong></p><p></p><p></p><p><strong>$$\huge\underline\mathfrak\red{</strong><strong>Follo</strong><strong>w</strong><strong> </strong><strong>me</strong><strong> </strong><strong>}$