A ball is thrown at angle 30° above
horizontal from top of tower with 10 m/s .
The ball hit the ground at 17.3 m from foot
of tower then height of tower is
(a) 110 m
(b) 100 m
(c) 10 m
(d) 12 m
Answers
Answered by
3
Since (1/2)mv^2 = mgh*sin30°
50=10*h*1/2
100/10=h
h=10m (option c)
shri6634:
How did you equal Kinetic energy and potential energy?
By the law of conservation of energy
K+U= constant
This question was from Projectile motion chapter. So i expected a quite different solution. Anyways thank you.
ohk
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