A ball is thrown at angle 45o from horizontal with 50 2 ml sec. Find out time of flight and range.
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Given v=20ms
−1
,θ=30
o
,H=45m.
a. As the ball has been projected at an angle of 30
o
above horizontal, so first of all we need to analyse the velocity horizontally and vertically. This will be useful while using distance-time relation in horizontal and vertical directions.
v
xi
=vcos30
o
=20×
2
3
=10
3
ms
−1
v
yi
=vsin30
o
=20×
2
1
=10ms
−1
It will be easy for us to use distance-time relation in vertical as it will involve less calculation.
In y-direction: −45=10t−
2
1
×gt
2
⇒t
2
−2t=0
which on solving gives t=1+
1
0s (positive value), (other value is 1−
1
0s, a negative value of time is not acceptable).
b. v
yf
=10−10×(1+
1
0)=−10
1
0ms
−1
v
f
=
v
yf
2
+v
xf
2
=
(10
1
0)
2
+(10
3
)
2
=10
3
ms
−1
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