A ball is thrown at different angles with the same
speed u and from the same point; it has the same
range in both the cases. If y, and y, be the heights
attained in the two cases, then y, + y2 =....
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Answer:
u^2/2g
Explanation:
R1 = u^2 sin2(x1)/g
R2 = u^2 sin2(x2)/g
since R1= R2
x2 = 90-x1
H1= u^2 sin^2(x1)/2g
H2 =u^2 sin^2(x2)/2g
y1 + y2 = u^2/2g ( sin^2(x1) + cos^2(x1))
y1 + y2 = u^2/2g × 1
y1 + y2 = u^2/2g
Note :
sin(90-x1) = cosx1
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