A ball is thrown directly upward with an initial velocity of 20m/s. How high does the ball go (assuming the ball leaves the person's hand at the 0m position)?
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Initial Velocity (u) = 20 m/s
Acceleration due to gravity (g) = -9.8 m/s²
.... Taken the value of 'g' as negative as the ball is going upwards which is against the gravitational pull of Earth
Final Velocity (v) = 0 m/s
Taking 'h' as Height,
v² = u²-2gh
0 = (20)² - [2*9.8*h]
0 = 400 - 19.6h
19.6h = 400
20.4 m is the Height.
I hope this helps.
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