Physics, asked by sharonmaladhari, 1 day ago

A ball is thrown down from top of a building of hight 12om with speed of 10m/s find the velocity and height after 2 sec

Answers

Answered by vibekanandac15

0

Answer:

speed - 50m/s and distance - 80m from bottom

formula used v^2-u^2= 2as

s = ut+1/2at^2

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