a ball is thrown downward with a speed v from the top of a tower. it reaches the ground with a velocity 3v.what is the height of tower?
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Answered by
22
we know ,v2=u2+2gh....here as the particle is move downward along gravitational force so here sign between u2 &2gh is positive
so, (3v)2=(v)2 +2gh
or, 9v2=v2 +2gh
or, 8v2=2gh
or,h=4v2/g.........
it is the ans.....
so, (3v)2=(v)2 +2gh
or, 9v2=v2 +2gh
or, 8v2=2gh
or,h=4v2/g.........
it is the ans.....
prakharsingh2018:
According to me answer is as follows:-
v2=u2+2gh
(3v)2=v2+2×10×h
9v2-v2=20h
8v2=20h
8v2/20=h
Hence,h=2v2/5
Answered by
2
it is given in question
u = v
v = 3v
a = g
so on putting the values in the equation v^2 - u^2 = 2gs
s = 4v^2/g = 0.4v^2
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