Question

A ball is thrown downwards with the speed of 20m/s from the top of the building 150 feet high and simultaneously another is thrown vertically upward with the speed of 30 m/s from the bottom of the building find the time after which the balls will meet

Answer 1

Answer:

3 s

Explanation:

let h be the height  reached by the second ball when it meets the first

h = 30t - gt²/2

150 - h = 20t +gt²/2

50t = 150

t = 3 s