Question

a ball is thrown from a field with a speed of 12 m/s at an angle 45 degree with the horizontal , at what distance will it hit the field again. g = 10m/s^2

Answer 1

Answer :-

14.4 m is the distance at which the ball hits the field from the point of projection.

Explanation :-

Horizontal range :

u²sin2θ/g

Substituting :

(12 m/s)²sin(2 × 45°)/10 m/s²

144 m²/s²/10 m/s²

14.4 m