a ball is thrown from a field with a speed of 12 m/s at an angle 45 degree with the horizontal , at what distance will it hit the field again. g = 10m/s^2
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Answer :-
14.4 m is the distance at which the ball hits the field from the point of projection.
Explanation :-
Horizontal range :
u²sin2θ/g
Substituting :
(12 m/s)²sin(2 × 45°)/10 m/s²
144 m²/s²/10 m/s²
14.4 m
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