a ball is thrown from a field with the 12m/s at an angle of 45° with the horizontal at what distance will it hit the field again.
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is it 14.5 m .....,,, I think .
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Answer:
According to the Question
It is given that ball is thrown from the roof with a speed of of 15m/s at an angle of 45° with the horizontal .
we need to calculate the distance will it hit the field again.
As we know that acceleration due to gravity is 10m/s².
Using horizontal range formula
- Let the distance will it hit the field be d metres .
- horizontal range = u²sin2∅/g
Substitute the value we get
➻ horizontal range = 15²Sin(2×45)/10
➻ horizontal range = 225×Sin90°/10
➻ horizontal range = 225×1/10
➻ horizontal range = 225/10
➻ horizontal range = 22.5m
Hence, the ball hits the roof again 22.5 metres from the point of projection .
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