A ball is thrown from a height H and another from 2h what is the ratio of time taken by the two balls to reach the ground
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1:2 as because the g will get cancelled out and since v=0 the ratio of ht= ratio of time
nishantprabhat4:
actually 1is to rooot 2
your answer is not correct
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s = ut + 1/2at1 2
s=h
h = 4.9 t1 2
t1 = √h/4.9
t2 = √2h/4.9
t1:t2 = 1:√2
s=h
h = 4.9 t1 2
t1 = √h/4.9
t2 = √2h/4.9
t1:t2 = 1:√2
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