a ball is thrown from ground level just clear 4m high at a distance of 4m and falls at a distance of 14m from the wall the magnitude of velocity the ball will be
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Given :
Range =R=4+14=18m
y=xtanθ (1-x/R)
x=4m, y=4m
4=4tanθ(1-4/18)
=4tanθ(7/9)
tanθ=9/7
θ= tan ⁻¹(9/7)--------(1)
Range R= u²sin2θ/g
=2(u²/g )(sinθcosθ)
18=(2xu²/9.8)[(9/√130)x(7/√130)]
18=[2u²/9.8]9x7/130
u²=18x130x9.8/2x9x7
u²=182
u=√182 m/s
∴ u=√182 m/s and θ= tan ⁻¹(9/7)
Range =R=4+14=18m
y=xtanθ (1-x/R)
x=4m, y=4m
4=4tanθ(1-4/18)
=4tanθ(7/9)
tanθ=9/7
θ= tan ⁻¹(9/7)--------(1)
Range R= u²sin2θ/g
=2(u²/g )(sinθcosθ)
18=(2xu²/9.8)[(9/√130)x(7/√130)]
18=[2u²/9.8]9x7/130
u²=18x130x9.8/2x9x7
u²=182
u=√182 m/s
∴ u=√182 m/s and θ= tan ⁻¹(9/7)
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