A ball is thrown from the ground with a velocity of 20 root 3 metre per second at the angle of 60 degree with the horizontal ball will hit the ground after t second will be
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Answer:
A particle is projected horizontal and the initial horizontal component of the velocity of the projected particle
V
h
=
20
√
3
, This will remain unchanged during its flight.
The initial vertical component of the velocity of the projected particle
V
v
=
0
. This will change with time during its flight by the action of gravitational pull @
g
=
10
m
/
s
2
Let after
t
sec from start the particle's velocity velocity makes angle
θ
=
60
∘
with the initial velocity in horizontal direction.
After
t
sec from start its vertical component will be
V
'
v
=
V
v
+
t
×
g
=
0
+
10
t
=
10
t
m
/
s
So
V
'
v
V
h
=
tan
θ
⇒
10
t
20
√
3
=
tan
60
∘
=
√
3
⇒
t
=
2
sec
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