A ball is thrown from the top of a tower. it reaches the ground with a velocity of 60ms ^-1 in 6 seconds. find the height of the tower ( take g = 10 ms^-2)
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given, final velocity(v) = 60ms^-1
initial velocity (u). = 0ms^-1
time taken (t). = 6seconds
acceleration due to gravity (g)= 10ms^-2
from equation v^2 - u^2 = 2as
60×60 - 0 × 0 = 2 × 10 × s
3600 = 20 × s
s = 3600/20
s = 180 m
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