Question

A ball is thrown from the top of a tower. it reaches the ground with a velocity of 60ms ^-1 in 6 seconds. find the height of the tower ( take g = 10 ms^-2)​

Answer 1

Answer:

given, final velocity(v) = 60ms^-1

initial velocity (u). = 0ms^-1

time taken (t). = 6seconds

acceleration due to gravity (g)= 10ms^-2

from equation v^2 - u^2 = 2as

60×60 - 0 × 0 = 2 × 10 × s

3600 = 20 × s

s = 3600/20

s = 180 m