Question

A ball is thrown from top edge as la vertical tower at t=0 if the horizontal and vertical directions are taken x and y respectively and the origin as the foot of the tower, the position ball any time t in given by x=21m, y = 80-5t²m. How far from foot of the tower (in m) on. the horizontal ground does the ball strike. If the height of the tower 80m​

Answer 1

Hence

u=0

a=tv−u

v=20secm

For the second ball the ball is thrown with initial speed 20secm and t=2sec

S=ut+21at2

By substituting the given values in above equation we get

S=60m

Hence, the height of the tower is 60m