Question

a ball is thrown horizontally at a speed of 24 meter per second from the top of a cliff,
if the ball hits the ground 4 second later approximately how high is the cliff?​

Answer 1

Answer:78.4 m

Explanation:

To obtain the height of the cliff; We can use the Relation to obtain the final velocity, vv = u + ata = acceleration due to gravity = 9.8m/s²v = 0 + (9.8*4)v = 0 + 39.2v = 39.2 m/sTo obtain the Height, Sv² = u² + 2aS39.2^2 = 0 + 2(9.8)S39.2^2 = 0 + 19.6S1536.64 = 19.6SS = 1536.64 / 19.6S = 78.4 m