Question

A ball is thrown horizontally from a point "A" travels along a straight line and strikes the wall to a point "B" which is at a distance of 10m and rebounds to the same point "A" is 8 sec. Find the average speed and average velocity of the ball​

Answer 1

Given:

A ball is thrown horizontally from a point "A" travels along a straight line and strikes the wall to a point "B" which is at a distance of 10m and rebounds to the same point "A" is 8 sec.

To find:

• Average speed

• Average velocity

Calculation:

Average speed is defined as the total distance divided by the total time taken to cover the distance.

$\therefore \: avg. \: speed = \dfrac{distance}{time}$

$= > \: avg. \: speed = \dfrac{2s}{8}$

$= > \: avg. \: speed = \dfrac{2 \times 10}{8}$

$= > \: avg. \: speed = \dfrac{10}{4}$

$= > \: avg. \: speed = 2.5 \: m {s}^{ - 1}$

Average velocity is defined as the total displacement divided by the total time taken to cover that displacement.

$\therefore \: avg. \:velocity= \dfrac{displacement}{time}$

In this case , displacement will be zero because the starting and the stopping point of the object is same.

$= > \: avg. \:velocity= \dfrac{0}{8}$

$= > \: avg. \:velocity= 0 \: m {s}^{ - 1}$

So, average speed is 2.5 m/s and average velocity is 0 m/s.