Question

A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 100 m horizontally away from and below the point of release. What is the speed of the ball just before it strikes the ground

Answer 1

Answer:  well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.  

The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]  

so t = sqrt(2*100/9.8) = 4.52s.  

The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s  

The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.  

so the final velocity is = sqrt(44.3^2 + 14.4^2) = 46.6m/s

Explanation: yes

Answer 2

Explanation:

hope this will helps u to solve your problem