Question

A ball is thrown horizontally from the top of a cliff. At a given moment of the trajectory, its velocity vector forms an angle with the horizontal. Obtain a formula for as a function of the horizontal distance the ball has traveled from the edge of the cliff (d) and the height it has descended from the top of the cliff (h).

• tg x = d/h
• tg x = 2d/h
• tg x = 4d/h
• tg x = h/d​

Answer 1

Answer:

1111111111111111111999999999999999999999999999999999999999444444444444444444444444

Explanation:

Answer 2

Given,

Distance from the edge of the cliff = d

Height descended from the top of the cliff= h

To find,

The function of the horizontal distance

Solution,

Using the formula,

The horizontal distance in terms of horizontal velocity and height of the cliff is given as,

Horizontal distance =  $(Horizontal velocity)\frac{\sqrt{2(Height of the cliff)} }{gravitational field strength}$

As, is it seen that Horizontal distance is directly proportional to the height of the cliff.

Hence, option 4 is the correct answer