A ball is thrown horizontally from the top of a tower and strikes the ground in 3 second at an angle of 30° with the vertical find the height of the tower and find the speed with which the body was projected
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Explanation:
Thrown horizontally: Vertical component of velocity present only due to acceleration due to gravity.
H= 1/2*gt^2
H= 1/2*10*9
H= 45m
Assuming horizontal velocity of projection of the body to be =u,
the vertical component of velocity reached in moving for 3s
=>v=gt=10×3=30m/s
=> tan30=1/√3=v/u
u=√3×30
u=51.9615243m/s
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