A ball is thrown horizontally with a velocity of 5 m/sec from the top of a tall building. The ball falls through 44.1 m before hitting a vertical wall. The distance of the wall from the building is 5x (in metre). Find x.
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A ball is thrown horizontally with a velocity of 5 m/sec from the top of a tall building. The ball falls through 44.1 m before hitting a vertical wall. the distance of the wall from the building is 5x
To find : the value of x.
solution : this question is based on concept of horizontal projectile.
see figure, here situation is clear.
h = 44.1 m , u = 5 m/s and g = 9.8 m/s
you should use formula, R = u√(2h/g)
= 5√(2 × 44.1/9.8)
= 5√(44.1/4.9)
= 5 × 3
= 15 m
but distance of wall from the building is 5x
so, 5x = R = 15 ⇒x = 3
Therefore the value of x = 3
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