Question

A ball is thrown horizontally with speed 10 m//s from the top of tower of height 80 m. After how much time and at what horizontal distance from the tower it strikes the ground ?

Answer 1

Answer:

Time taken = 4 s

Horizontal distance covered = 40 m

Explanation:

In horizontal projectile motion, the time period is same as that of a freely falling body from the same height.

So,

t = √(2H/ g).............(1)

=√(2 x 80/10)

=√16

= 4 s

Now along the horizontal direction (i.e. x axis),

s = ut + 1/2at²

i.e., x = ut + 1/2(0)t² [Since there is no acceleration along horizontal direction, a = 0]

=> x = ut

=> x = u . √(2H/ g) (From 1)

Here , 'x' , which the horizontal distance covered, is same as that of the range(R)

On substitution,

R = 10 x 4

= 40 m

Hope it helps.

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