Question

A ball is thrown in air . Its height at any time is given by h= 3+14t-5t^2 find the maximum height it can reach ?​

Answer 1

Answer:

26.25

Step-by-step explanation:

h = -5t^2+14t+3 is in form ax^2+bx+c

a=-4, b=14, c=4

here a<0 so it has maximum value =(4ac -b^2)/4a, occurs at x=-b/2a

maximum height = -4×4×14-14^2/(-4×4)

=-420/(-16) =26.25

occurs when t=-14/-5=2.8