Physics, asked by kumarvardhan565, 6 hours ago

a ball is thrown in air making some angle with the horizontal considering buoyancy due to air which is equal to 1/50th weight of the ball ,percentage change in range of ball is​

Answers

Answered by Anonymous
1

Answer:

Correct option is

D

67.5

The acceleration is g both horizontally and vertically.

time of flight =t=

g

2usin

horizontally s =ut+

2

1

at

2

s=

g

ucosθ(2usinθ)

+(0.5)g(

g

2usinθ

)

2

s=(

g

1

)[u

2

sin2θ+2u

2

sin

2

θ]

for maximum ; s =

ds

=0

g

u

2

[2cos2θ+4sinθcosθ]=0

[cos2θ+sin2θ]=0 or tan2θ=−1

θ=

2

135

o

=67.5

o

so,angle the ball should be thrown so that it travels the

maximum horizontal distance =67.5

o

hence, option D is correct.

Answered by divinesha2007
0

Answer:

98℅

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