Question

A ball is thrown in the air. Its height at any
time t & is given by
H = 3+14+ - 5t2, find the maximum
ht. if can reach.​

Answer 1

Answer:

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Step-by-step explanation:

If the flight of an object is expressed by a quadratic equation in the form of ax²+bx+c, the time taken to reach max height will be found at t=-b/2a. So, here it is:

t=-4/2(-2)

=-4/-4

=1 second

Then:

h=4–2+3

=5m as the max height