Question

A ball is thrown in vertically upward with 20m/s reaches at amax hight in 10 s. Find the
hight attained by the ball?​

Answer 1

Explanation:

u = 20 , t = 10s , g = 9.8

h = ut +1/2g(t^2)

h = 300 + 1/2(9.8)100

h = 300 + (4.9)100

h = 300+490

h = 790

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Answer 2

Answer:

initial velocity=20m/s

final velocity=0m/s

v2=u2-2gh

0=40-2×10×h

38÷10=h

20=h