Question

A ball is thrown into the air with an initial upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h (t) = – 16t^2 + 48t + 4. What is the ball’s maximum height? (note: the ball is thrown into the air from a height 4ft above the ground) *

1 point

44 ft

40 ft

32 ft

4 ft

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Answer 1

Answer:

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Step-by-step explanation:

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