A ball is thrown straight up, from 3 m above the ground, with a velocity of 14 m/s. When does it hit the ground?
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thodi der baad aake giregi naaa
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By considering upward motion as +ve we will get equation as
S=ut+1/2at^2
here S=-3
u=14
a=-10
By solving this equation you will get your answer t=3sec
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