Math, asked by laxgoaliesforlife, 4 months ago

A ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s. Its height above the ground after x seconds is given by the quadratic function y = -16x2 + 32x + 3. Explain the steps you would use to determine the path of the ball in terms of a transformation of the graph of y = x2.

Answers

Answered by soumyajaisal
1

Answer:

ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s. Its height above the ground after x seconds is given by the quadratic function y = -16x^2 + 32x + 3. Explain the steps you would use to determine the path of the ball in terms of a transformation of the graph of y = x^2.

Answered by elektra0921
0

Answer: Complete the square to write the equation in vertex form:

y = -16(x - 1)2 + 19.

Suggest that the graph of the parent function is narrowed, reflected across the x-axis, and then translated 1 unit to the right and 19 units up.

on edge

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