Question

A ball is thrown straight up from the ground with an unknown velocity. It reaches its
highest point after 3.5 s. With what velocity did it leave the ground?

Answer 1

Answer:

Hey bro .. Here's ur answer

Explanation:

please refer the attachment...

Answer 2

here is your ans.

let unknown velocity = x

acceleration acting on the ball = 10m/so in oposite direction.

now, by :- v = u + at

at highest point V equal to zero-

so, 0 = u -10×3.5

u = 35m/sec. ans.

hope it helps ☺