Question

A ball is thrown straight up with a velocity of 16 m/s; what will be its velocity 2.0s after
being released?

Answer 1

Answer is 3.6 meter per second

Answer 2

Concept Introduction:

In this numerical equation of motion is used where v=u+at

Given: Velocity at which the ball is thrown as $16$m/s; t=$2$s.

To Find:

We have to find the value of, velocity after $2$s from the ball is thrown.

Solution:

According to the problem,

u= $16$m/s ; t= $2$s; g=$10 \frac{m}{s^{2} }$; v=?

We know, $v=u+at$

⇒v= $16+10*2=16+20=36m/s$

Final Answer:

The value of velocity after $2$s is: $36m/s$.

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