Question

A ball is thrown straight up with a velocity of 16 m/s. What will be its velocity 2.0s after being released?

Answer 1

Explanation:

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Answer 2

Given :-

A ball is thrown straight up with a velocity = 16 m/s

To Find :-

The velocity 2.0s after being released.

Analysis :-

Using the first equation of motion, substitute the given values in the question and find the required accordingly.

Solution :-

We know that,

• v = Final velocity
• a = Acceleration
• u = Initial velocity
• t = Time

By the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Initial velocity (u) = 16 m/s

Acceleration = 9.8 m/s

Time (t) = 2 sec

Substituting their values,

v = 16 - 9.8(2)

v =16 - 19.6

v = -3.6 m/s

Therefore, the comes down with velocity 3.6 m/s at 2 sec.