A ball is thrown straight upward with a speed v from a point h meter above the ground.the time taken for the ball to strike the ground is
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t_max height=v/g=20/9.8=2.04 secs
d=1/2 gt²
=4.9(4.165)
=20.4m above the building
If v_final=30 m/s, then:
v_final=√2gh
(30)²=900=2 x 9.8 x h
=19.6h
h=45.92
45.92–20.4=25.52m as the height of the building
d=1/2 gt²
=4.9(4.165)
=20.4m above the building
If v_final=30 m/s, then:
v_final=√2gh
(30)²=900=2 x 9.8 x h
=19.6h
h=45.92
45.92–20.4=25.52m as the height of the building
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