a ball is thrown straight upwards into the air within initial velocity of 20 metre per second how long will it take to the ball to reach at a height of 15 m how fast will lead them be going take jiske to 10 metre per second square
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Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t ′ ) 2
t' =3s
Total time= 3+2= 5s
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