Question

a ball is thrown to the height h and it comes down with the same velocity find the change in momentum and totak change in momentum. ​

Answer 1

Answer:

CHANGE IN MOMENTUM IS

$2m \sqrt{2gh} .$

Step-by-step explanation:

$height \: = h \\ \\ {0}^{2} - {v}^{2} = - 2gh \\ \\ \\ \\ v = \sqrt{2gh} \\ \\ change \: in \: momentum = m(v - ( - v)) \\ \\ = 2mv \\ \\ = 2m \sqrt{2gh} .$