A ball is thrown up and attains a maximum height of 100 m. What is its initial speed
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s = 100m. v = 0. a = -10m/sec u = ?
By the third equation of motion,
v^2 = u^2 + 2as
0 = u^2 + 2*(-10)*100
0 = u^2 + -2000
u^2 = 2000
Therefore,
u = √2000
u = 10√20 = 20√5
Ans: The initial speed was 20√5 m/sec.
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