Question

A ball is thrown up at a speed of 4 m/s. The
maximum height reached by the ball and the correct v-t
graph will be (take g = 10m/s²). Plsssss plsssss plsssss answer for this question. Fast fast!!! ​

Answer 1

Answer:

0.8 m

Explanation:

let us take vertical velocity as positive y axis

so,

u= 4m/s. a= 10m/s^2

At the highest point velocity becomes zero, using the formula as

v^2 = u^2 + 2as

0= 4^2 -(2× 10×s )

- indicates the opposite direction of acceleration

16=20s

s = 16/20

= 0.8 m

Therefore the ans is 0.8 m